Dataspider string index out of range: -1
Webif guess in word: print ("\nYes!", guess, "is in the word!") # Create a new variable (so_far) to contain the guess new = "" i = 0 for i in range (len (word)): if guess == word [i]: new += … WebThis works, because the loop starts at zero, and ends at Length-1 because index is no longer less than Length. This, however, will throw an exception: for (int index = 0; index <= array.Length; index++) { Console.WriteLine (array [index]); } Notice the <= there? index will now be out of range in the last loop iteration, because the loop thinks ...
Dataspider string index out of range: -1
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Webコンストラクタと説明. StringIndexOutOfBoundsException () 詳細メッセージなしで StringIndexOutOfBoundsException を構築します。. StringIndexOutOfBoundsException … WebI am getting "String index out of range: -1" error while using 'Select' Database connector I am using this query to select certain columns from oracle table: select emp_onboard.emp_id, emp_fin.emp_salary,emp_apr.per_inc from emp_fin, emp_onboard, emp_apr where emp_fin.emp_id=emp_apr.emp_id and …
WebJul 13, 2010 · The string abcde has index start from 0 to 4, but the substring () method takes startIndex and endIndex as arguments based on the fact that I can call foo.substring (0) and get "abcde". Then why does substring (5) work? That index should be out of range. What is the explanation? WebOct 18, 2016 · String Index out of range Exception in jdbc programming. I have a database table consisting of 6 columns and 6 rows. I want to access all 6 column values of the 2nd …
WebSep 21, 2024 · Try using syntax like this: String.format ("INSERT INTO USERS (first_name, last_name, etc...) VALUES (%s, %s, etc...); It will return a string dynamically created by … WebNov 23, 2013 · 1 I am getting the following error when calling a function from within my class: java.lang.StringIndexOutOfBoundsException: String index out of range: -1 Although I used a system prints to see the inputs I am passing in the substring () function and everything seems to be right.
WebJun 2, 2012 · When indexOf () returns -1, it means that the value couldn't be found in the String. So, in this case, you're searching a String for '.' which doesn't exist in the String. …
WebApr 9, 2024 · Apr 9, 2024 at 0:57. 1. As the answer in the post I linked says: "it is thrown to indicate that an index of some sort (such as to an array, to a string, or to a vector) is out … lampada bola ledWebFeb 23, 2024 · You "parameters" are inside a string literal, so JDBC won't see them (even if it did recognize named parameters). More often than not it's much easier to used filtered … jess andrea instagramWebGive me the light! :D. java.lang.StringIndexOutOfBoundsException: String index out of range: 13113 at java.lang.String.checkBounds (String.java:401) at java.lang.String. … jessangoWebSorted by: 3 Use for i in range (len (s)-1) or g!=len (s)-1 len () gives you the total number of characters, which will be the index of the character after the last one since indexing starts at 0. You can get rid of the if g!=0 and g!=len (s) part all together if you use for i in range (1,len (s)-1) Share Improve this answer Follow jessandniko.minted.usWebOct 24, 2024 · You take phrase.indexOf ('S') on a string without checking the return value. If there is no match, the method returns -1. You then use this index as the upper bound of a substring, which crashes the program. You would want a different algorithm even if you got it correct, if I understand correctly what you want to do. jessa nefrologieWebNov 19, 2012 · What you could probably do is to retain the FileInputStream, get the contents of the file and put into a String by using a recursive fis.read and adding the char in a … jess and patsWebJun 25, 2024 · java.lang.StringIndexOutOfBoundsException: String index out of range: -1 at java.base/java.lang.StringLatin1.charAt (StringLatin1.java:47) at java.base/java.lang.String.charAt … jessandmike.co.uk